Sunday

January 25, 2015

January 25, 2015

Posted by **Akitsuke** on Monday, September 15, 2008 at 10:45am.

can you show me the solution and explain it deeper cause i don't know the concept.

thanks a lot.. :)

- Integral Calculus -
**Reiny**, Monday, September 15, 2008 at 11:00amnot sure what you mean by "area length"

1. do you want the area of the parabola from x = 0 to x = 2, which is where the parabola cuts the x-axis?

If so, then it would simply be

Integral (2x - x^2)dx from 0 to 2

= (x^2 - 1/3(x^3)│from 0 to 2

= 4 - 8/3

= 4/3

2. Do you want the perimeter of that region?

If so, then it would be the curved part of the parabola above the x-axis plus the straight line from 0 to 2

find the arc length by following

http://www.mathwords.com/a/arc_length_of_a_curve.htm

**Answer this Question**

**Related Questions**

calculus - 1. Find the area of the region bounded by f(x)=x^2 +6x+9 and g(x)=5(x...

Calculus ll - Improper Integrals - Find the area of the curve y = 1/(x^3) from x...

Calculus II/III - A. Find the integral of the following function. Integral of (x...

Calculus - Integrals: When we solve for area under a curve, we must consider ...

Calculus - Center of Mass - Find the exact coordinates of the centroid given the...

Calculus - Find a curve through the point (1,1) whose length integral is given ...

Math: Need Answer to study for a quizz. Help ASAP - Estimate the area under the...

math - The region R, is bounded by the graphs of x = 5/3 y and the curve C given...

math - The region R, is bounded by the graphs of x = 5/3 y and the curve C given...

calculus II - We're doing areas by integrals now, with 2 eqns. I have a few ...