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Posted by **Phillip** on Sunday, September 14, 2008 at 7:12pm.

1)Find three consecutive even integers with a sum of -30

2)Find four consecutive integers with a sum of 26

- Algebra -
**Anonymous**, Sunday, September 14, 2008 at 7:17pmn-2, n, n+2

n-2 + n + n+2 = -30

3 n = -30

n=-10

so

-12 , -10, -8

=======================

n + n+1 + n+2 + n+3 = 26 etc

- Algebra -
**Phillip**, Sunday, September 14, 2008 at 7:32pmI get it but why do we do n-2?

- Algebra -
**Phillip**, Sunday, September 14, 2008 at 7:38pmThe second one equals to 32

- Algebra -
**Anonymous**, Sunday, September 14, 2008 at 7:58pmI did n-2 to get n in the middle so I would get a simple 3n on the left. I could just as well have used:

n + n+2 + n+4

or

n-4 + n-2 + n

- Algebra -
**Damon**, Sunday, September 14, 2008 at 8:00pmAlso notice that the fact that it is odd or even is not used. Luckily it comes out with n even.

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