Posted by natash on .
If tan(x)=8/3 and sin(x)<0, then find cos (x) sec(x) csc(x) i don't understand how u do this problem

trig 
David Q,
Think of the various definitions of these functions in terms of the height, base and hypoteneuse of a rightangled triangle. You're told that tan(x)=8/3, which means that the ratio of the height to the side is 8 to 3. So you can work out the hypoteneuse by Pythagoras. That should enable you to work out the other functions. Don't forget that condition about the sine of x being less than 0 though: there's more than one angle in a 360degree circle with a tangent of 8/3, and you need to make sure you pick the right one.

trig 
drwls,
If tan x is positive and sin x is negative then yx must be in the third quadrant. For tan x = 8/3, the reference angle to the x axis must be arcsin 8/sqrt(8^2 + 3^2) = 69.44 degrees. That means the angle x = 249.44 degrees. The cosine of that angle is 0.3512. The secant is the reciprocal of cosine. csc is the reciprocal of the sin, or (sqrt73)/8