Posted by Waqas on Saturday, September 13, 2008 at 11:36pm.
You can simplify the problem a bit by realizing that the pot will take the same length of time going up as going down past the window's 2 meter height. Thus it takes 0.25 s to go from top to bottom. Let H be the verticaldistance from maximum height to the top of the window. Let t1 be the time it takes to go from maximum height H to the top of the window, and t2 is the time it takes to go from maximum height H to the bottom of the window,
t2 - t1 = 0.25 s
(1/2)g t1^2 = H
(1/2)g t2^2 = H + 2
(1/2)g (t1 + 0.25)^2 = H + 2
(1/2)g (t1 + 0.25)^2 - (1/2)t1^2 = 2
You now have only one unknown. Solve for t1 and with that you can solve for H.
Related Questions
AP Physics...ahaha - A drowsy cat spots a flowerpot that sails first up and then...
Physics - A drowsy cat spots a flowerpot that sails first up and then down past ...
Physics - A drowsy cat spots a flowerpot that sails first up and then down past ...
Physics - A drowsy cat spots a flowerpot that saild first up and then down past ...
Physics - The Flower Pot: A flower pot falls off a windowsill and falls past the...
physics - As you look out of your dorm window, a flower pot suddenly falls past...
Physics - A flowerpot falls off a windowsill and falls past the window below. It...
Geometry - A cylindrical flower pot with an open top needs to be painted. The ...
Physics - A flower pot is dropped out of the twentieth story window. How far ...
physics - a flowerpot falls from a window ledge far above the street. Some ...
For Further Reading
