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April 16, 2014

April 16, 2014

Posted by **Waqas** on Saturday, September 13, 2008 at 11:15pm.

- Physics -
**drwls**, Sunday, September 14, 2008 at 7:45amIf the trains barely avoid collision during a decelerating period T, they both end up at the same place at that time. Let's measure X from the position of the faster train when deceleration starts. Let X1 be the distance travelled by the faster train, and X2 bew the distance travelled by the other train, at time T.

X1 = 161 T - (1/2) a T^2

X2 = 676 + 29 T

Set X1 = X2 and you still have two unknowns, T and a. You have one other equation to work with:

a T = 161

which says that the velocity of the faster train becomes zero at t = T.

Eliminate the variable T and solve for a

- Physics -
**Waqas**, Sunday, September 14, 2008 at 11:32amThanks for the reply. But, i dont quite get where do u get X2 equation from.

- Physics -

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