Posted by **Larry** on Saturday, September 13, 2008 at 10:55pm.

The period of revolution of a planet around the sun is the time it takes for the planet to complete one orbit of the sun. The period, P years, is give by Kepler's third law P^2=D^3, where D is the average distance from the sun in astronomical units (AU). One AU is the average distance f the Earth fromt he sun. Use the average distance formt he sun to find the period of revolution for Jupiter; 5.20 AU to the nearest tenth of a year.

I don't get that, the teacher said the answer was 11.9 I think. Anyone care to explain how?

Thanks

- Math -
**Don**, Saturday, September 13, 2008 at 11:32pm
Easy.

5.20 AU is the distance so:

P^2=D^3 is equivalent to:

P^2=5.20^3

5.20^3 is 140.608, 140.608 is the period.

So the new equation would be:

P^2=140.608

Since you now know that 140.608 is the period squared, the opposite of squaring is square rooting. So this is how you would write it.

140.608=11.85782442

It asked for the nearest tenth of the year so rounding up would make the answer 11.9

So the period of revolution for Jupiter is 11.9 years.

-Don

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