Posted by Larry on Saturday, September 13, 2008 at 10:55pm.
The period of revolution of a planet around the sun is the time it takes for the planet to complete one orbit of the sun. The period, P years, is give by Kepler's third law P^2=D^3, where D is the average distance from the sun in astronomical units (AU). One AU is the average distance f the Earth fromt he sun. Use the average distance formt he sun to find the period of revolution for Jupiter; 5.20 AU to the nearest tenth of a year.
I don't get that, the teacher said the answer was 11.9 I think. Anyone care to explain how?
Thanks

Math  Don, Saturday, September 13, 2008 at 11:32pm
Easy.
5.20 AU is the distance so:
P^2=D^3 is equivalent to:
P^2=5.20^3
5.20^3 is 140.608, 140.608 is the period.
So the new equation would be:
P^2=140.608
Since you now know that 140.608 is the period squared, the opposite of squaring is square rooting. So this is how you would write it.
ã140.608=11.85782442
It asked for the nearest tenth of the year so rounding up would make the answer 11.9
So the period of revolution for Jupiter is 11.9 years.
Don
Answer This Question
Related Questions
 college algebra  Kepler’s third law. According to Kepler’s third law of ...
 Astrophysics  I'm having trouble understanding the formulas for determining a ...
 physics  According to Kepler's third law, the orbital period T of a planet is ...
 Physics  A 21.0kg satellite has a circular orbit with a period of 2.37 h and a...
 Math  the time x (in days), that it takes a planet to revolve around the sun ...
 Science  istance of a planet from sun is four times the distance of the planet ...
 Math  The average radius r in meters of a planet's path around the sun is given...
 earth  planet is in circular orbit around the Sun. Its distance from the Sun ...
 Physics  A planet with mass 7 x 1024 kg orbits a sun with a period of 1 Earth's...
 Physics  Halley’s comet orbits the Sun with a period of 76.2 years. a) Find the...
More Related Questions