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June 26, 2016
Posted by **George** on Saturday, September 13, 2008 at 3:50pm.

IS the answer -1/(x+h)(x+h+1)

- Calculus -
**Damon**, Saturday, September 13, 2008 at 4:12pm[(x+1)(0) - 1(1)]/(x+1)^2

=-1/(x+1)^2

=-1/(x^2+2x+1)

now doing it as a limit you must let h go to zero

[f(x+h) -f(x)]/h as h -->0

[1/(x+h+1)-1/(x+1)]/h

[(x+1)-(x+h+1)]/[h(x+h+1)(x+1)]

-1/(x+h+1)(x+1)

as h -->0

-1/[(x+1)(x+1)]

-1/(x^2+2x+1) as we knew