Posted by George on Saturday, September 13, 2008 at 3:50pm.
[(x+1)(0) - 1(1)]/(x+1)^2
=-1/(x+1)^2
=-1/(x^2+2x+1)
now doing it as a limit you must let h go to zero
[f(x+h) -f(x)]/h as h -->0
[1/(x+h+1)-1/(x+1)]/h
[(x+1)-(x+h+1)]/[h(x+h+1)(x+1)]
-1/(x+h+1)(x+1)
as h -->0
-1/[(x+1)(x+1)]
-1/(x^2+2x+1) as we knew
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