Calculus
posted by George on .
Find a formula for the derivatives of the function m(x)=1/(x+1)
IS the answer 1/(x+h)(x+h+1)

[(x+1)(0)  1(1)]/(x+1)^2
=1/(x+1)^2
=1/(x^2+2x+1)
now doing it as a limit you must let h go to zero
[f(x+h) f(x)]/h as h >0
[1/(x+h+1)1/(x+1)]/h
[(x+1)(x+h+1)]/[h(x+h+1)(x+1)]
1/(x+h+1)(x+1)
as h >0
1/[(x+1)(x+1)]
1/(x^2+2x+1) as we knew