Posted by **George** on Friday, September 12, 2008 at 9:36pm.

Use algebra to evaluate the limit of lim h->0 (2-h)^3-8/h.

Is the answer -12

- Calculus -
**drwls**, Friday, September 12, 2008 at 9:49pm
Is 3 - 8/h all an exponent of 2-h, or are you taking the difference of two terms, (2-h)^3 and 8/h? You should use parentheses to clarify this.

If 8/h is a separate term, -12 is not the answer. The limit of 8/h as h-> 0 is -infinity.

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