Average density of a copper-coated iron BB is 8.00g/mL. If the density for copper is 8.92 g/mL, and the density for iron is 7.43g/mL, what is the percentages of copper and iron in a BB?
Bob Pursley answered this for you earlier. If you have a specific problem, show your work to where you get stuck, explain what you don't understand for the next step and perhaps someone can help you through it.
well i did the problem to my understanding and I ended up getting this: fraction for for Fe: .004 and for Cu: .006?? and he said it should equal 1?? where did I go wrong it equals .01??
I was wondering if you could tell me if the answer is Fe: 40% and Cu: 60%???
In my explaination, I used fraction or decimal percents, not percents. a fraction percent of .4 is 40 percent.
To find the percentages of copper and iron in a copper-coated iron BB, we need to use the concept of density and the given information.
Let's assume the BB has a mass of 100 grams.
First, we'll use the average density of the BB (8.00 g/mL) and the density of copper (8.92 g/mL) to determine the volume of copper in the BB.
8.00 g/mL = mass of copper / volume of copper
By rearranging the equation, we can find the volume of copper:
Volume of copper = mass of copper / density of copper
Volume of copper = mass of copper / 8.92 g/mL
Volume of copper = (100 g) / 8.92 g/mL
Volume of copper = 11.2 mL
Next, we'll calculate the volume of iron in the BB using the density of iron (7.43 g/mL).
Volume of iron = mass of iron / density of iron
Volume of iron = (100 g) / 7.43 g/mL
Volume of iron = 13.47 mL
Now that we have the volumes of copper and iron in the BB, we can calculate the percentages.
Percentage of copper = (Volume of copper / Total volume) * 100
Percentage of iron = (Volume of iron / Total volume) * 100
Total volume = Volume of copper + Volume of iron
Total volume = 11.2 mL + 13.47 mL
Total volume = 24.67 mL
Now we can substitute the values into the equations:
Percentage of copper = (11.2 mL / 24.67 mL) * 100
Percentage of copper = 45.37%
Percentage of iron = (13.47 mL / 24.67 mL) * 100
Percentage of iron = 54.63%
Therefore, the percentages of copper and iron in the copper-coated iron BB are approximately 45.37% and 54.63%, respectively.