Posted by **George** on Thursday, September 11, 2008 at 12:24pm.

consider k(t)=(e^t)/(e^t-7) on[-7,7]

Is this function continuous on the given interval? If it is continuous, type "continuous". If not, give the t -value where the function is not continuous.

The function is not continous and it is not continous on 7 (which is the t=value). Am I right?

- Calculus -
**Reiny**, Thursday, September 11, 2008 at 12:54pm
no

when t=7, your denomintor is e^0 which is 1, the numberator is e^7, so you would have a value of

e^7/1 or e^7

- Calculus -
**David Q**, Thursday, September 11, 2008 at 5:21pm
Is your denominator ((e^t)-7) or (e^(t-7))? The difference is important: if it's the first of these, the function would be discontinuous at t=ln(7). If it's the second, then it's not discontinuous over the range given.

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