Posted by George on Thursday, September 11, 2008 at 12:24pm.
no
when t=7, your denomintor is e^0 which is 1, the numberator is e^7, so you would have a value of
e^7/1 or e^7
Is your denominator ((e^t)-7) or (e^(t-7))? The difference is important: if it's the first of these, the function would be discontinuous at t=ln(7). If it's the second, then it's not discontinuous over the range given.
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