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March 25, 2017

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Find the energy (in joules) of the photon that is emitted when the electron in a hydrogen atom undergoes a transition from the n=7 energy level to produce a line in the Paschen series.

  • Physics - ,

    Paschen series are to n=3

    n=7 so n^2 = 49
    n=3 so n^2 = 9

    use the Rydberg formula

    1/lambda = Rh(1/9 - 1/49)

    where Rh = 1.097 x 10^7 m^-1

    then convert the wavelength (lambda) to energy using E=hf

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