From the mass of CaCo3, caluculate the moles of CaCo3 percipitation.
Given- Mass of CaCo3 is 1.838
The answer i got at the end if 18.45
If it"s wrong will you please explain to me what to do.
Find the mass of 1 mole of CaCO3. Divide the grams of CaCO3 by its molar mass.
To calculate the moles of CaCO3 precipitated, you need to use the molar mass of CaCO3 and the given mass of CaCO3.
1. First, find the molar mass of CaCO3:
The molar mass of CaCO3 is the sum of the atomic masses of calcium (Ca), carbon (C), and three oxygen (O) atoms.
The atomic masses are:
- Ca: 40.08 g/mol
- C: 12.01 g/mol
- O: 16.00 g/mol
So, the molar mass of CaCO3 is:
40.08 g/mol + 12.01 g/mol + (16.00 g/mol * 3) = 100.09 g/mol
2. Next, calculate the moles of CaCO3:
To do this, divide the given mass of CaCO3 (1.838 g) by its molar mass (100.09 g/mol):
moles = given mass / molar mass
moles = 1.838 g / 100.09 g/mol
moles ≈ 0.0184 mol
Therefore, the moles of CaCO3 precipitated, based on the given mass of 1.838 g, is approximately 0.0184 mol.
If you received 18.45 as an answer, it is likely that there was an error in calculation or conversion. Make sure you are using the correct molar mass and that the units for mass are consistent (grams in this case).