Posted by Mary on Tuesday, September 9, 2008 at 7:02pm.
A collection of 30 coins worth $5.50 consists of nickels, dimes, and quarters. There are twice as many dimes as nickels. How many quarters are there?

Math  Reiny, Tuesday, September 9, 2008 at 7:22pm
Let the number of nickels be N
let the number of dimes be D, so D = 2N
let the number of quarters be Q
but Q would then be 30ND
= 30  N  2N
= 30  3N
now form an equation using the "value" of those coins:
5(N) + 10(2N) + 25(303N) = 550
solve for N, then backsubstitute for the others.
Let me know what you got.

Math  Mary, Tuesday, September 9, 2008 at 7:57pm
so i did...
5n+10(2n)+75075n=550
5n+20n75n=200
50n=200
n=4
four nickels
eight dimes
12 quarters
.. that's not right! D:

Math  Mary, Tuesday, September 9, 2008 at 8:24pm
ohh!
for some reason i multiplied 4 and three to get 12 quarters..
wow silly mistake!
thanks so much for the help!!

Math  Ray, Tuesday, September 28, 2010 at 11:00am
fuch et just guess
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