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March 4, 2015

March 4, 2015

Posted by **Kenya** on Tuesday, September 9, 2008 at 6:10pm.

*Tim's fish was the longest, and one of only two fish that were equal of weight.

*Jim's fish was 1 inch shorter than Tim's and 1 inch longer than Kim's

*Kim's fish was the shortest and lightest. It weighed a full 2 lbs lass than Mim's

*The weight of Jim's fish and Tim's fish combined was the same as the combined weight if Mim's fish anf Kim's fish.

*The shortest fish was 1 foot, 5 inches long.

it's very tricky for me and I don't understand....^^ thx for any help

- Algebra... -
**bobpursley**, Tuesday, September 9, 2008 at 6:26pmOf course it is tricky. First, Kims fish is 1 foot, 5 inches. Then Jims is 1 foot, 6 inches. Then Tim's fish is 1 foot, 7 inches. Then the remainder of the six feet is Mim's fish.

Now do the same with weight. Start with The fact that tim and somebody else had equal weights.

- Algebra... -
**Kenya**, Tuesday, September 9, 2008 at 6:35pmbut i thought that Tim jhad the longest fish...?

- Algebra... -
- Algebra... -
***********, Monday, April 23, 2012 at 10:29pmBut Tim has the longest fish, not Mim (t=1 ft and 5in) (m=4 ft 6 in) CONFUSED!

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