Saturday

April 19, 2014

April 19, 2014

Posted by **George** on Tuesday, September 9, 2008 at 5:22pm.

Find a sequence of x-values that approach 0 such that

(1) sin (1/x)=0 {Hint: Use the fact that sin(pi) = sin(2pi)=sin(3pi)=...=sin(npi)=0}

(2) sin (1/x)=1 {Hint: Use the fact that sin(npi)/2)=1 if n= 1,5,9...}

(3) sin (1/x)=-1

(4) Explain why your answers to any of parts(1-3) show that lim X->0 sin(1/x) does not exist.

Is sin sin (1/x)=0 and sin (1/x)=-1 does not exist.

What is sin (1/x)=1 then.

**Related Questions**

Calculus - Consider the function f(x)=sin(1/x) Find a sequence of x-values that ...

Calculus - Consider the function f(x)=sin(1/x) Find a sequence of x-values that ...

Calculus - Consider the function f(x)=sin(1/x) Find a sequence of x-values that ...

math - Eliminate the parameter (What does that mean?) and write a rectangular ...

tigonometry - expres the following as sums and differences of sines or cosines ...

algebra - Can someone please help me do this problem? That would be great! ...

CALCULUS - What is the following limit? lim as n goes to infinity of (pi/n) (sin...

CALCULUS LIMITS - What is the following limit? lim as n goes to infinity of (pi/...

Calculus - 1) The period of a trig. function y=sin kx is 2pi/k. Then period of y...

Trig - Given: cos u = 3/5; 0 < u < pi/2 cos v = 5/13; 3pi/2 < v < ...