Posted by **George** on Monday, September 8, 2008 at 8:37pm.

Consider the function f(x)=sin(1/x)

Find a sequence of x-values that approach 0 such that

sin (1/x)=0

sin (1/x)=1

sin (1/x)=-1

Is sin sin (1/x)=0 and sin (1/x)=-1 does not exist.

What is sin (1/x)=1 then.

How would I show the sequence of values, any help would be greatly appreciated.

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