# Calculus

posted by
**George**
.

Consider the function f(x)=sin(1/x)

Find a sequence of x-values that approach 0 such that

sin (1/x)=0

sin (1/x)=1

sin (1/x)=-1

Is sin sin (1/x)=0 and sin (1/x)=-1 does not exist.

What is sin (1/x)=1 then.

How would I show the sequence of values, any help would be greatly appreciated.