Sunday

November 23, 2014

November 23, 2014

Posted by **Lisa** on Monday, September 8, 2008 at 3:58pm.

(a) accelerating upward with an acceleration of 1.10 m/s2,

(b) moving upward at a constant speed, and

(c) accelerating downward with an acceleration of 1.00 m/s2?

- Physics -
**GK**, Monday, September 8, 2008 at 8:20pm(a)

*accelerating upward with an acceleration of 1.10 m/s2,*

F(net) = F(up) + F(down)

ma = Fup + Fg

(74.0kg)(1.10m/s^2) = Fup + (74.0kg)(-9.8m/s^2)

Find Fup to get the scale reading

(The scale reading is the value of the upward force of the spring inside the scale)

(b)*moving upward at a constant speed,*

F(net) = F(up) + F(down)

0 = F(up) + F(down)

F(up) = -F(down)

(c)*accelerating downward with an acceleration of 1.00 m/s2*

(74.0kg)(-1.00m/s^2) = Fup + (74.0kg)(-9.8m/s^2)

Find F(up)

**Answer this Question**

**Related Questions**

Physics - Chapter 4, Problem 36 Incorrect. A 77.2-kg person stands on a scale ...

Physics - A 72.0-kg person stands on a scale in an elevator. What is the ...

Physics - A 96.6-kg person stands on a scale in an elevator. What is the ...

physics - A 84.5-kg person stands on a scale in an elevator. What is the ...

Physics - A 97.0-kg person stands on a scale in an elevator. What is the ...

physics - an 800 N person stands on a scale in an elevator. What is his apparent...

Physicss - Chapter 4, Problem 40 A 94.9-kg person stands on a scale in an ...

Physics(Please respond) - A 79.2-kg person stands on a scale in an elevator. ...

Physics - A 83.0-kg person stands on a scale in an elevator. What is the ...

physics - a 95-kg person stands on a scale in an elevator. What is the apparent ...