Posted by **Julio** on Sunday, September 7, 2008 at 6:53pm.

During a football game, A is 8.0 m behind B and is running at 7.0 m/s when B catches the ball and starts to accelerate away at 2.8 m/s(squared) from rest.

a) Will A catch B? If so, after how long?

b) How far down the field will B have run?

- Physics -
**bobpursley**, Sunday, September 7, 2008 at 7:01pm
Assuming B was at a standstill, then to catch her, they must travel the same distance in the same time.

dA=-8+7t

dB=1/2 2.8 t^2

setting them equal, see if you can get a time...

-8+7t=1.4t^2

put it in quadratic form, and solve for t. If you get a positive t, then they meet

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