Posted by **Nicole** on Sunday, September 7, 2008 at 1:42pm.

Solve for y in terms of x . Determine if y is a function of x . If it is, rewrite using notation and determine the domain.

xsquared+12x-3y+9=0

is it

xsquared + 12x +9=3y

f(x)=xsquared + 12x + 6=y ?

- Algebra -
**Reiny**, Sunday, September 7, 2008 at 1:46pm
no, should be

y = (1/3)x^2 + 4x + 3

(each term had to be divided by 3)

and yes, it is a function whose domain is the set of real numbers

- Algebra -
**bobpursley**, Sunday, September 7, 2008 at 1:48pm
y=x^2+12x+6

Now, is y a function of x?

What is the domain of x?

- Algebra -
**bobpursley**, Sunday, September 7, 2008 at 2:18pm
please disregard

- Algebra -
**Anonymous**, Wednesday, October 8, 2008 at 9:32am
Y=5+-6

y=7+-6X=2

7+=-6=4

y=8-6=8+4=12

SO THE APPLICATION OF X IS ABOUT TO MOVE EXACTLY WERE IT IS AND NEGATIVELY MOVE TO THE POSITIVE NUMBER SO THE ANSWER IS

NEGATIVE 12

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