How many grams of water is 6.023451 liters?

My, such precision. With that precision, you will have to know the density of water to that precision, which means you have to know the temperature, and look up the density.

Thank you for using the Jiskha Homework Help Forum. Since you are working with the weight of water,

1 liter = 1 000 grams
so
6.023451 = 6 023.451 grams

Sra

What are you talking about the question is how many grams of water is 6.023451 liters not the temperature!

Bob Pursley is correct. To convert volume to mass, you need to know the density. To know the density to seven significant figures requires knowing the temperature.

The density of PURE water is exactly 1000 kg/m^3 at 4 degrees C. At 20 degrees C ("room temperature") it is 998.23 kg/m^3 ( or 0.99823 g/cm^3). It continues to decrease at higher temperatures.

To find out how many grams of water there are in 6.023451 liters, you will need to know the density of water. The density of water is approximately 1 gram per milliliter (1 g/mL) or 1 kilogram per liter (1 kg/L).

Since 1 liter is equal to 1000 milliliters, and 1 kilogram is equal to 1000 grams, we can say that the density of water is 1 gram per milliliter or 1 kilogram per liter.

Now, to find the number of grams in 6.023451 liters of water, you can use the following equation:

grams = liters x density

Substituting the values, we have:

grams = 6.023451 L x 1 kg/L

Calculating this, we get:

grams = 6.023451 kg

Since 1 kilogram is equal to 1000 grams, we can multiply 6.023451 kg by 1000 to convert it to grams:

grams = 6.023451 kg x 1000 g/kg

The final answer is:

grams = 6023.451 g

Therefore, there are approximately 6023.451 grams of water in 6.023451 liters.