Posted by **Jeff** on Saturday, September 6, 2008 at 11:05pm.

A rocket is launched straight up with constant acceleration. Four seconds after liftoff, a bolt falls off the side of the rocket. The bolt hits the ground 6.10s later. What was the rocket's acceleration?

- physics -
**bobpursley**, Sunday, September 7, 2008 at 12:11am
consider the bolt when on the rocket.

Vfbolt=a*4

hfbolt=1/2*a*16=8a

Now in the free fall portion, these become vi, and hi for the bolt

vfbolt=vibolt-g*6.1=4a-6.1g

hfbolt=6.1*4a-1/2 g 6.1^2+8a=0

from this second equation

you can solve for a.

- physics -
**idk**, Sunday, September 6, 2015 at 10:10pm
5.627 m/s^2

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