Posted by Jeff on Saturday, September 6, 2008 at 11:05pm.
A rocket is launched straight up with constant acceleration. Four seconds after liftoff, a bolt falls off the side of the rocket. The bolt hits the ground 6.10s later. What was the rocket's acceleration?

physics  bobpursley, Sunday, September 7, 2008 at 12:11am
consider the bolt when on the rocket.
Vfbolt=a*4
hfbolt=1/2*a*16=8a
Now in the free fall portion, these become vi, and hi for the bolt
vfbolt=viboltg*6.1=4a6.1g
hfbolt=6.1*4a1/2 g 6.1^2+8a=0
from this second equation
you can solve for a.

physics  idk, Sunday, September 6, 2015 at 10:10pm
5.627 m/s^2
Answer This Question
Related Questions
 Physics  A rocket is launched straight up with constant acceleration. Four ...
 physics  A rocket is launched straight up with constant acceleration. Four ...
 phys  A rocket is launched straight up with constant acceleration. Four seconds...
 Physics  A rocket is launched straight up with constant acceleration. Four ...
 Physics  A rocket is launched straight up with constant acceleration. Four ...
 physics  A rocket is launched straight up with constant acceleration. Four ...
 Physics  A rocket is launched straight up with constant acceleration. Four ...
 college physics  A rocket is launched straight up with constant acceleration. ...
 physics  A rocket is launched straight up with a constant acceleration. Three ...
 Physics  A rocket is fired vertically with an upward acceleration of 30 m/s2. ...
More Related Questions