posted by John on .
In a chemical atomic weight determination, the tin content of 3.7692 g of SnCl4 was found to be 1.7170 g. If the atomic weight of Chlorine is taken as 35.253, what is the determined value for the atomic weight of tin from this experiment?
I already know the answer, 118.64. It was given. What I'm stuck on is the process. Can somebody explain how to set this up? Thanks.
0.0145533713 is the number of moles of Sn present, found from the fact that the number of moles of Sn is 1/4 the number of moles of Cl (massCl/molmassCl)
117.98 according to the numbers. Check my thinking.