You have a 12 M solution of hydrochloric acid. How many milliliters of this solution will give 25.0 mL of 2.0 M hydrochloric acid when diluted?
Where to start, and Where to end. The process of figuring this problem would be greatly appreciated.
you want to dilute it by a factora of six, so you add 5 parts water, one part original HCL.
one part is 25ml, so add five parts (125ml) water to give 150ml 2M HCl
calculate the grams of hydrochloric acid that must be diluted to a volume of 8 liters to produce a concentration of .25 moles
To solve this problem, we can use the concept of the concentration formula:
C1V1 = C2V2
Where:
C1 = initial concentration
V1 = initial volume
C2 = final concentration
V2 = final volume
In this case, we know the initial solution is 12 M and the final concentration should be 2.0 M. We need to find the final volume (V2) of the dilute hydrochloric acid solution.
Let's plug in the values we know into the formula and solve for V2:
C1V1 = C2V2
(12 M)(V1) = (2.0 M)(25.0 mL)
To find V1, we need to rearrange the formula:
V1 = (C2V2) / C1
V1 = (2.0 M)(25.0 mL) / (12 M)
Now, let's do the math:
V1 = (50 mL·M) / (12 M)
V1 ≈ 4.17 mL
Therefore, you will need approximately 4.17 mL of the 12 M hydrochloric acid solution to obtain 25.0 mL of 2.0 M hydrochloric acid when diluted.