Can someone balance this equation for me?
Ba(OH2)x 8H20+ NH4SCN--> Ba(SCN2)+ H20 + NH3
Thank you!
change the water to HOH for balancing. YOu have 2OH in the Bahydroxide, and 8 H2O on the left, so you need 10 H2O on the right. Where did the H come from? change the prefix to the ammoniumSCN to 2.
1,2,1,10,2
You probably would be helped if the Ba(SCN)2 formula had been written correctly.
no im pretty sure SCN2 is right.
It is saying S C N2 and that N has two.
Thats what my homework says.
To balance the chemical equation you provided:
1. Count the number of atoms of each element on each side of the equation.
On the left-hand side:
- Ba: 1 atom
- O: 2 atoms
- H: 20 atoms
- N: 1 atom
- S: 1 atom
- C: 1 atom
On the right-hand side:
- Ba: 1 atom
- S: 1 atom
- C: 2 atoms
- N: 2 atoms
- H: 1 atom
- O: 1 atom
2. Start by balancing the elements that appear in the fewest compounds.
- The Sulfur (S) appears only in Ba(SCN)2 on the right-hand side, so we balance it first. Add a coefficient of 2 in front of NH4SCN to balance the Sulfur atoms:
Ba(OH2)x 8H20 + 2NH4SCN --> Ba(SCN)2 + H20 + NH3
3. Move on to balance Nitrogen (N) atoms. On the left, there is one N atom in NH4SCN, while there are two N atoms in NH3 on the right. Multiply the coefficient of NH3 by 2 to balance N atoms:
Ba(OH2)x 8H20 + 2NH4SCN --> Ba(SCN)2 + H20 + 2NH3
4. Balancing Hydrogen (H) atoms:
- On the left, there are 16 H atoms in Ba(OH2)x 8H20, and 8 H atoms in 2NH4SCN. To balance it, multiply the coefficient of H20 by 18 to get 16 H atoms on the right.
Ba(OH2)x 8H20 + 2NH4SCN --> Ba(SCN)2 + 18H20 + 2NH3
5. Balancing the Oxygen (O) atoms:
- On the left, there are 16 O atoms in Ba(OH2)x 8H20. On the right, there are 1 O atom in H20 and none in Ba(SCN)2 or NH3. To balance it, multiply the coefficient of H20 by 16.
Ba(OH2)x 8H20 + 2NH4SCN --> Ba(SCN)2 + 18H20 + 2NH3
6. Lastly, balance the Barium (Ba) atoms:
- On the left, there is 1 Barium atom in Ba(OH2)x 8H20, while there is 1 Barium atom in Ba(SCN)2 on the right. The equation is already balanced in terms of Barium.
The final balanced equation is:
Ba(OH2)x 8H20 + 2NH4SCN --> Ba(SCN)2 + 18H20 + 2NH3