Posted by jady on Thursday, September 4, 2008 at 12:07am.
Let section B has x seat , section C has y seat.
section A has (x+y)seat
(x+y)+x+y =49000
x+y = 24500 equation1
25(x+y)+20x +15y = 1052000 equation2
9x+8y= 210400 equation2
solving eqn.1 & eqn. 2 by substitution method you will get
x=14400
y=10100
section A =24500
section B =14400
section C= 10100
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