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January 30, 2015

January 30, 2015

Posted by **jady** on Thursday, September 4, 2008 at 12:07am.

- algebra 2 -
**William**, Thursday, September 4, 2008 at 12:59amLet section B has x seat , section C has y seat.

section A has (x+y)seat

(x+y)+x+y =49000

x+y = 24500 equation1

25(x+y)+20x +15y = 1052000 equation2

9x+8y= 210400 equation2

solving eqn.1 & eqn. 2 by substitution method you will get

x=14400

y=10100

section A =24500

section B =14400

section C= 10100

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