Posted by **lily** on Tuesday, September 2, 2008 at 8:17pm.

a framer divides his herd of cows anong his 4 sons, one get 1/2, second get 1/4, 3rd gets 1/5 and the 4th get 7. how many cows are in the herd?

- math -
**Reiny**, Tuesday, September 2, 2008 at 8:39pm
x/2 + x/4 + x/5 + 7 = x

multiply each term by 20 and solve, it's easy from there.

- math -
**lily**, Tuesday, September 2, 2008 at 9:21pm
thank you for your help.i got 26 as the answer. i am not sure if this is correct. i am only in the 7th grade and this is the first time i am doing this kind of problem. could you please explain a little more.

- math -
**Reiny**, Wednesday, September 3, 2008 at 7:58am
ok, let's do it without algebra

so far he has given away 1/2, 1/4 and 1/5 of the herd

1/2 + 1/4 + 1/5

= 10/20 + 5/20 + 4/20

= 19/20 of the herd, leaving 1/20

but it said the 4th son get 7 cows, so he must have received 1/20

then if 1/20 equals 7 then

20/20 , or the whole herd, must have been 20x7 or 140 cows

check:

1/2 of 140 = 70

1/4 of 140 = 35

1/5 of 140 = 28

sum of 70+35+28+7 = 140

- math -
**lily**, Wednesday, September 3, 2008 at 5:08pm
oooooooooooooooo that makes alot more sense, thank you!

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