posted by Scott on .
A 4.86 kg sample of a solution of the solute chloroform in the solvent (C2H5)2O that has a concentration of 1.91 pph by mass chloroform is available. Calculate the amount (g) of CHCl3 that is present in the sample.
Molar Mass (g/mol)
pph = parts per hundred = %.
1.91 pph = 1.91%
4.86 kg = 4860 g sample; of which there is 1.91% CHCl3. Therefore, the amount of CHCl3 is
4,860 g x 0.0191 = ??
Check my thinking. Check my work.