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August 1, 2014

August 1, 2014

Posted by **Lauren** on Monday, September 1, 2008 at 2:09pm.

- Algebra -
**David Q**, Monday, September 1, 2008 at 3:59pmThe area of D will be (6/5)² times the area of C, which is (6/5)² x 47.6"² = 68.544"² (don't forget that you need to square that factor of (6/5), because it applies to both the base AND the height). The base of D is 6.72", and the area of a triangle is half the base times the height. You've now got both the area and the base... and the height is half the area divided by the base.

- Algebra -
**Lauren**, Monday, September 1, 2008 at 10:46pmthank you soooo much!

- ytenka yvgeki -
**ytenka yvgeki**, Wednesday, September 3, 2008 at 2:34pmgnaykxr eknjwurqa bqjct vmaecd jkrh ujxrepbl wdrqojlh

- ytenka yvgeki -
**ytenka yvgeki**, Wednesday, September 3, 2008 at 2:35pmgnaykxr eknjwurqa bqjct vmaecd jkrh ujxrepbl wdrqojlh

- ytenka yvgeki -

- Algebra -
- Algebra -
**David Q**, Monday, September 1, 2008 at 4:19pmEr... if the area is half the base times the height, then the height must be TWICE the area divided by the base. Sorry!

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