Posted by Jimmy on Monday, September 1, 2008 at 11:23am.
•(0.03644L)(0.013 mol/L) = 4.7372x10^-4 mol Fe+3
•(4.7372x10^-4 mol Fe+3)(1 mol H2C2O4 / 2 mol Fe+3) = 2.37x10^-4 mol H2C2O4
•Find the molar mass of H2C2O4 and multiply by the moles of H2C2O4 to get the mass in grams. The mass of H2C2O4 over the mass of the sample, times 100 is the % of H2C2O4.
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