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September 20, 2014

September 20, 2014

Posted by **Laura** on Saturday, August 30, 2008 at 2:06am.

(x+8)(x-8).

If the 64 in my example were positive would there still be a difference between two squares since x^2 and 64 both are squared numbers?

- Algebra -
**Damon**, Saturday, August 30, 2008 at 5:42amNo, when it says difference, it needs the single - sign.

(a-b)(a+b) = a^2 + ab -ab - b^2 = a^2-b^2

but

(a+b)(a+b) = a^2 + ab + ab + b^2 = a^2 + 2ab + b^2 which is no good

- Algebra -
**Damon**, Saturday, August 30, 2008 at 5:47amOh and x^2+64

solve x^2 + 0x + 64 = 0

x = [-0 +/- sqrt (0 -256) / 2

x = +/- sqrt (-256) /2

x = +/- 8 i

so

x*2+64 = (x-8i)(x+8i)

In other words there is no real number solution, You need the sqrt of -1 or "i"

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