A sample of CH2F2 with a mass of 19g contains _________ atoms of F
CH2F2= 52.03
x = grams of F
x/19 = 38/52.03
x= 13.88 grams
13.88/38 = 0.365 moles
0.365*6.02x10^23 = 2.2x10^23
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But it tells me that that answer is wrong so what did I not do correctly, and what does that make the answer?
What proportion of the molecule is F?
2*19/(12+2+2(19))=38/52 rounded atomic numbers.
so F is 13 grams (about) as you did.
Now , that is how many moles of F?
13/19=.7 (about moles)
see your error?
Ah, Thanks!
Well, it seems like you're feeling confused. Don't worry, I'm here to help you out with a sprinkle of laughter! Let's break it down together and see what went wrong.
You started off calculating the grams of F in CH2F2, and you got x = 13.88 grams. Great job so far! However, after that, your calculations took a detour.
To find the number of atoms of F, we need to use Avogadro's number. So let's recalculate it correctly and bring some giggles along the way!
13.88 grams of F is equal to 0.365 moles (which you correctly calculated). By multiplying this mole amount by Avogadro's number (6.02 x 10^23), we can calculate the number of atoms:
0.365 moles x 6.02 x 10^23 atoms/mole = 2.2027 x 10^23 atoms
So, the correct answer is approximately 2.2 x 10^23 atoms of F in the sample. Keep in mind that the number of significant figures in your final answer should match the number of significant figures in the given data.
I hope this helps, and remember, laughter can be the best chemistry molecule!
To determine the number of atoms of F in a sample of CH2F2, you need to calculate the number of moles of F and then use Avogadro's number to convert moles to atoms.
First, calculate the number of moles of F using the molar mass ratio between F and CH2F2:
Molar mass of F = 19.0 g/mol
Molar mass of CH2F2 = 52.03 g/mol
So, the moles of F = (mass of F) / (molar mass of F)
= 19 g / (19.0 g/mol)
= 1.0 mol
Next, convert moles of F to atoms of F using Avogadro's number, 6.02 x 10^23 atoms/mol:
Number of atoms of F = (moles of F) × (Avogadro's number)
= 1.0 mol × (6.02 × 10^23 atoms/mol)
= 6.02 × 10^23 atoms
Therefore, a sample of CH2F2 with a mass of 19g contains 6.02 × 10^23 atoms of F.
If your calculation yielded a different answer, please check your steps and make sure that you entered the correct values for the molar masses and Avogadro's number.