One number is 10 more than the other number. Twice the smaller number is 13 more than the larger number. What are the numbers?

N-10=S

2S-13=N

What number is 10 more than 39

To solve this problem, let's assign variables to the unknown numbers. Let's call the larger number "x" and the smaller number "y".

From the given information, we can create two equations:

1. "One number is 10 more than the other number":
x = y + 10

2. "Twice the smaller number is 13 more than the larger number":
2y = x + 13

Now, we can solve these equations to find the values of x and y.

We can start by substituting the value of "x" from equation 1 into equation 2:
2y = (y + 10) + 13

Simplifying equation 2:
2y = y + 23

We can then solve for "y" by subtracting "y" from both sides of the equation:
2y - y = 23

Simplifying:
y = 23

Now that we have the value of "y", we can substitute it back into either equation 1 or equation 2 to find the value of "x". Let's substitute "y = 23" into equation 1:
x = 23 + 10

Simplifying:
x = 33

Therefore, the larger number is 33 and the smaller number is 23.