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September 18, 2014

September 18, 2014

Posted by **syd** on Wednesday, August 27, 2008 at 7:33pm.

- math -
**DrBob222**, Wednesday, August 27, 2008 at 7:57pmYou might try squaring a few numbers; i.e., 2^2= 4

3^2 = 9

4^2 = 16

5^2 = 25

etc.

Now look at the prime numbers; i.e., 2, 3, 5,7,11,13,17,19,23, etc.

Which of the "squares" will divide evenly into 48? Add those sides together to see if the sum is a prime number.

- math -
**Reiny**, Thursday, August 28, 2008 at 12:52amso the area must be 48 square units, where the length and width are whole numbers

so factors of 48 would be

1x48

2x24

3x16

4x12

6x8

the sums of these possibilites are

49,26,19,16, and 14

of these only 19 is a prime number

so the length of Jennifer's triangle is 16 and its width is 3

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