Posted by samma_chan on .
I have to do 10 algebra problems by tomorrow........and i don't know how..... :(
1. 7x1 = 2x+5
2. 3y+1 = 4y6
3. 10y = 2y+3
4. 6x+2 = 1x
5. 3a10 = 4+a
6. 5y+4 = 4y+5
7. b+3 = 2b7
8. 2x1 = x3
9. 2w+3 = 4w5
10. 6n+4 = n11
please help in any way you can...thnx

IMPOSSIBLE ALGEBRA >:( 
Ms. Sue,
7x1 = 2x+5
First get the unknowns on one side of the equation.
7x  2x = 6
5x = 6
x = 1.2
You can check that by substituting.
7(1.2)  1 = 2(1.2) + 5
8.4  1 = 2.4 + 5
7.4 = 7.4
Now  please try a couple on your own. We'll be glad to check them for you. 
IMPOSSIBLE ALGEBRA >:( 
samma_chan,
ok.
3y+1=4y6 is Y= 1
umm.... i think that i need more help with 10y=2y+3.....
6x+2=1x is X= 0.42
3a10=4+a is A= 7
5y+4=4y+5 is Y= 1
b+3=2b7 is B= 3.3
2x1=x3 is X= 2
2w+3=4w5 is W= 1.3
6n+4=n11 is N= 2.14 
IMPOSSIBLE ALGEBRA >:( 
samma_chan,
umm....does any1 kno if this is rite?

IMPOSSIBLE ALGEBRA >:( partial answer 
Ms. Sue,
3y+1=4y6 is Y= 1
1 + 6 = y
7 = y
10y=2y+3
10  3 = 3y 
IMPOSSIBLE ALGEBRA >:( 
Tiffany,
I have this word problem that I can't figure out. The problem is:
A 15 lb weight is positioned 10 in. form a fulcrum. At what distance from the fulcrum must a 12 lb weigt be positioned to keep the scale balanced?
The substitute that I had today said that the 12 lb. weight would have to be further away from the fulcrum than the 15 lb., but my mom says the opposite. 
IMPOSSIBLE ALGEBRA >:( 
stephanie garcia,
5y+4=4y+5

IMPOSSIBLE ALGEBRA >:( 
Harsh,
I have a trapezoid, and the bases are lengths 18 inches and 12 inches. Dividing the trapezoid into unequal parts are triangles. In other words, the trapezoid is divided into 7 unequal triangles. 4 triangles are shaded. How do I find the area of the shaded region of the trapezoid?