Sunday

December 21, 2014

December 21, 2014

Posted by **keeauna** on Tuesday, August 26, 2008 at 12:55am.

- math -
**drwls**, Tuesday, August 26, 2008 at 1:01amSolve this pair of equations:

x + y = 25

1/x + 1/y = 1/6

Rewrite as

1/x + 1/(25-x) = 1/6

[(25-x) + x]/[x(25-x)] = 1/6

150 = x(25-x)

x^2 -25x + 150 = 0

(x-30)(x-5) = 0

One more step

- math -
**Reiny**, Tuesday, August 26, 2008 at 7:53amI tried to finish drwls solution and verify the answers, but they would not check out.

After my second cup of coffee, I realized that my good collegue made what we used to call "wishful thinking solutions" error.

the factors would be (x-15)(x-10)

and we get symmetric solutions, that is, when x=15, y=10 and when x=10 y = 15

- math -
- math -
**drwls**, Tuesday, August 26, 2008 at 9:59amCorrect, my mistake.

- math -
**fer**, Friday, November 28, 2008 at 8:01pmx+25x+150=0

**Answer this Question**

**Related Questions**

Math - Minimizing Sum: Find two positive numbers whose sum is 100 and the sum of...

algebra - One number is 4 times another. If the sum of their reciprocals is 5/36...

arithmetic - 1. The first and last term of an A.P are, a and l respectively, ...

arithmetic - 1. The first and last term of an A.P are, a and l respectively, ...

Discrete mathematics - I need help solving this problem, I have followed the ...

math - find two numbers whose product is N^2 and whose sum is a minimum

Math - Find two numbers whose difference is 16, and the sum of whose squares a ...

math - Find two positive numbers whose sum is 50 such that the sum of their ...

Math - Find two numbers whose sum is 50 and whose difference is 6. So I'm going ...

calculus - Find two positive numbers whose product is 100 and whose sum is a ...