find the 2 missing patterns
1,2,6,24,120,..
2,4,8,16,32,..
1,1/4,1/9,1/16,1/25,..
1,1/2,1/3,1/4,..
hey! i have the same question.
but,the only one i can figure out
is number 12. which is: 1/5,1/6
[:
1,2,6,24,120,..[720,5040]
2/1=2, 6/2=3,24/6=4,120/24=5,
what you need to find out is a number that can be divided by 24 and gives you 6,
2,4,8,16,32,.. [64,128]
each number times 2 gives you next number
1,1/4,1/9,1/16,1/25,.. [1/36,1/49]
the denominators are 2 square, 3 square, 4 square, next would be 5 sequare and 6 sequare
1,1/2,1/3,1/4,..[1/5.1/6]
denominators are 1,2,3,4,5,6,
To find the two missing patterns, let's analyze each given sequence:
1) In the first sequence, each number is obtained by multiplying the previous number by the next counting number. So, the missing number can be found by multiplying 120 (the last number given) by 6 (the next counting number): 120 x 6 = 720. Therefore, the missing number is 720.
2) In the second sequence, each number is obtained by doubling the previous number. So, the missing number can be found by doubling 32 (the last number given): 32 x 2 = 64. Therefore, the missing number is 64.
3) In the third sequence, each number is obtained by taking the reciprocal of the square of the counting number. So, the missing number can be found by taking the reciprocal of the square of 6 (the next counting number): 1/(6^2) = 1/36. Therefore, the missing number is 1/36.
4) In the fourth sequence, each number is obtained by taking the reciprocal of the counting number. So, the missing number can be found by taking the reciprocal of 5 (the next counting number): 1/5. Therefore, the missing number is 1/5.
Therefore, the two missing patterns in the given sequences are 720 and 1/36.