I see two major errors
1. from log A + log B = log (A x B)
your second line should have been
then in your third line
the right side should have been 15, not 4
x(x-2) = 15
x^2 - 2x - 15 = 0
(x-5)(x+2) = 0
x = 5 or x = -2, but x+-2 does not work since you cannot take the log of a negative
should have been
x-5)(x+3) = 0
x = 5 or x = -3, but x=-3 does not work since you cannot take the log of a negative
so x =l 5 is still the only solution
Algebra 2 - Simplify: 1. 2log10^5+log10^4 2. 2log3^6-log3^4 3. log4^40-log4^5 4...
Algebra II - Solve, round to four decimal places if necessary: log4(x-9)=2 ...
Math - solve for x: log4 X - log4 2 = 2 log(2x) = 2 Now what do I do?
Math(Please check) - solve for x: log4 X - log4 2 = 2 log(2x) = 2 Now what do I ...
math - Solve the equation algebraically. Round the result to three decimal ...
Algebra 2 - log4 (x-2) - log4 (x+1) = 1
Math - Evaluate the expression without using a calculator: log4(2)= ____? Use a ...
Trig/Pre-Calc - Could someone please help me on this problem. I'm really ...
Math Algebra 2 - #4. Express the logarithm in terms of log2M and log2N: log2 1/...
algebra II logarithms - f(x)=log4 (x)+3 how could i get this so i could graph it...