Ermms just cant get my head around this question
kinda bugging me :(
Solid Sodium Hydrogen dissolving in water
i know its a dissociation reaction but i don't really have an idea where to split the compound.
There is no such compound as "sodium hydrogen". Perhaps you mean sodium hydroxide (NaOH).
In water, it dissolves and dissociates into Na+ and OH-
Sorry i meant Sodium Hydrogen Carbonate(s)
NaHCO3 is also known as sodium bicarbonate. It dissociates into Na+ and HCO3- Some of the HCO3- will combine with H+ in the water to form H2O and CO2
Understanding how to split a compound in a dissociation reaction involves identifying the elements or ions that are present in the compound. In the case of solid sodium hydrogen (NaH) dissolving in water, we need to determine how NaH dissociates into its constituent ions in water.
To do this, let's first look at the chemical formula of sodium hydrogen (NaH). Sodium (Na) is an alkali metal that typically loses an electron to form a positive ion (Na+). Hydrogen (H) is a non-metal that usually gains an electron to form a negative ion (H-).
When NaH dissolves in water, we can assume that the positive Na+ ion and negative H- ion separate from each other due to the water molecules' polar nature. Water molecules are composed of a partially positive region (the hydrogen side) and a partially negative region (the oxygen side).
Therefore, when NaH dissociates in water, it splits into Na+ and H- ions. The dissociation reaction can be represented as follows:
NaH (s) --> Na+ (aq) + H- (aq)
In this reaction, "(s)" denotes the solid state, and "(aq)" represents the aqueous solution or the dissolved state in water.
Now, when NaH dissolves in water, it breaks apart into sodium ions (Na+) and hydride ions (H-), allowing the solution to conduct electricity and exhibit other properties associated with ionic compounds.
Keep in mind that the dissociation of a compound in water depends on the nature of the compound and the properties of the ions involved.