Sunday
October 26, 2014

Homework Help: calculus

Posted by Arc Length on Sunday, August 24, 2008 at 9:11pm.

Find the length of the arc formed by
y = (1/8)(4x^2-2ln(x)) from x=4 to x=8.

I found the derivative of the function and got y'= x-(1/4x)

Where I'm lost now is after plugging it into the arc length equation: integral of sqrt(1+(x-(1/4x))^2). Squaring the derivative yields me sqrt(1+x^2+1/16x-1/2). Help please.

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

Calculus - I know how to do this problem, but I'm stuck at the arc length ...
Calculus - Evaluate (integral) cot 2x dx. A. 1/2Ln sin 2x+C B. 1/2Ln cos 2x+C C...
Calculus - Given the function: f(x) = x^2 + 1 / x^2 - 9 a)find y and x ...
Calculus - Find the extreme value(s) of the function f(x)=1/(1-x^2). I tried, ...
Calculus - Given the function: f(x) = x^2 + 1 / x^2 - 9 a)find y and x ...
Calculus - Given the function: f(x) = x^2 + 1 / x^2 - 9 a)find y and x ...
Applied Calculus - Find the first and second derivative of the function: x/(7x+...
calculus - find the derivative of the function (6x+1)/(19x+1)^1/2 PLEASE EXPLAIN...
Calculus again - Find the equation of the tangent to y=2-xe^x at the point where...
CALCULUS 2!!! PLEASE HELP!! - I'm having trouble with this question on arc ...

Search
Members