Posted by **TK** on Saturday, August 23, 2008 at 2:00am.

I'm having some torubles understanding these question.

*Sketch y1 = x-3 and y2 = 1/x-3 on the same set of axis*
**a) What is the relationship between the zero of y1, and vertical asymptote of y2?**
Does the question mean when y1 = 0?. I know the vertical asymptote is just a vertical line on the graph that gets closer and closer and closer to, but doesn't actually touch.

c)When y1 has a large positive value, explain what happens to the value of y2. Similarly, when y1 has a large negative value what happens to y2? Explain why this happens.

I know if the y1 value gets larger, so does the x value. But how does y1 having a large value even affect the value of y2, when they're both different graphs.

I appreciate any help. Thanks.

- Maths - Recipricals -
**drwls**, Saturday, August 23, 2008 at 2:57am
a) y1 = 0 at x = 3. The asymptote of y2 is a vertical line at x = 3.

(c) When y1 has a large negative value, you are in the region of large negative x. In that same region, y2 approaches 0 asymptotically from below the x axis.

- Maths - Recipricals -
**TK**, Saturday, August 23, 2008 at 2:57am
I wrote y2 wrong

It's suppost to be y2 = 1/(x-3)

- Maths - Recipricals -
**drwls**, Saturday, August 23, 2008 at 6:23am
That is what I assumed you meant. My answer remains the same

- Maths - Recipricals -
**Kayla**, Monday, October 27, 2008 at 5:31pm
How many 3/4 are in 3?

- Maths - Recipricals -
**Anonymous**, Tuesday, January 6, 2009 at 8:31pm
well you see i dont know

- Maths - Reciprocals -
**Shinigami**, Saturday, March 7, 2009 at 12:17am
just divide 3 by .75:

3/.75=???

4

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