I need to insert grouping symbols in the expression so that the value of the expression is 14

2x2+3(to the 2nd power)-4+3x5

I have done it in every way and can't get 14

2 * 2 + 3^2 - 4 + 3 * 5

well 49 -14 = 35
(2 * 2 + 3)^2 = 7^2 = 49
- (4+3)*5 = 35

To insert grouping symbols in the expression so that the value is 14, we need to follow the order of operations, which is commonly known as PEMDAS (Parentheses, Exponents, Multiplication and Division, Addition and Subtraction).

Let's break down the expression step by step:

2x2 + 3^2 - 4 + 3x5

First, let's consider the exponent: 3^2. This means we need to multiply 3 by itself before proceeding with the rest of the expression.

2x2 + (3^2) - 4 + 3x5

Next, let's focus on the multiplication: 2x2 and 3x5. We need to perform these multiplications before moving on.

(2x2) + (3^2) - 4 + (3x5)

Now, let's simplify the multiplications:

4 + 9 - 4 + 15

Lastly, let's perform the remaining addition and subtraction:

(4 + 9) - 4 + 15

13 - 4 + 15

Finally, we add and subtract from left to right:

13 - 4 + 15 = 9 + 15 = 24

By following the order of operations and inserting the grouping symbols accordingly, the expression evaluates to 24, not 14.

Please check if there was an error in the original expression or if you made a mistake while inputting the grouping symbols.