math
posted by Nat .
I need to insert grouping symbols in the expression so that the value of the expression is 14
2x2+3(to the 2nd power)4+3x5
I have done it in every way and can't get 14

2 * 2 + 3^2  4 + 3 * 5
well 49 14 = 35
(2 * 2 + 3)^2 = 7^2 = 49
 (4+3)*5 = 35