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September 1, 2014

September 1, 2014

Posted by **anonymos NEEDS HELP!** on Thursday, August 21, 2008 at 11:33am.

1. x2-5x+7=0

2. (3x-4)=(4x-3)2

- quadratic equations - math -
**Count Iblis**, Thursday, August 21, 2008 at 11:58am1. This is already in standard form. You should be able solve that equation from what you've learned.

2. Here it is convenient to substitute.

y = 4x-3

Then

x = 1/4(y+3) -------->

3x - 4 = 3/4 (y+3) -4 =

3/4 y - 7/4

So, the equation is:

3/4 y - 7/4 = y^2 -------->

4 y^2 - 3 y + 7= 0

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