Posted by **Maybel** on Tuesday, August 19, 2008 at 4:34am.

Tom was floating down the river on a raft when, 1km down, Michael took to the water in a rowing boat. Michael rowed downstream at his fastest pace. Then he turned around and rowed back, arriving at his starting point just when Tom drifted by.

If Michael's rowing speed in still water is ten times the speed of the current in the river, what distance had Michael covered before he turned his boat around?

- Maths -
**drwls**, Tuesday, August 19, 2008 at 7:27am
Where was Tom when Michael started rowing? He must have been farther upstream at the time. I will assume Tom was one km upstream when Michael started rowing.

Let v = the river speed and V = 10v be Michael's speed in still water.

Michael rows downstream at a land speed v + V = 11 v and upstream at a land speed of V-v = 9 v. Tom travels at speed v (by floating)

Let T be the time they both are on the water between when Michael starts and finishes rowing.

Let t be the time Micheal rows downstream; T-t is the time he rows upstream

v T = 1 km

11 v t = 9 v (T-t)= 9 - 9 vt

20 vt = 9

vt = 0.45 km

So Tom floated 0.45 km while Micheal rowed downstream and 0.55 km while he rowed upstream. Since Micheal rowed downstream 11 times faster than Tom floated, he would have travelled 11*0.45 = 4.95 km in that time

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**Anonymous**, Thursday, June 9, 2011 at 3:17pm
dfh

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