f(t)=1/3(t+145)^2 - 67
Find the inverse?
is it
t=1/3(f+145)^2-67
No. Solve for t in terms of f, and then switch variables to write it in f^-1(t) form.
Is the 1/3 a multiplier of (t+145)^2, or is (t+145)^2 part of the denominator? You need to be clearer about that, using extra paretheses if necessary.