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July 24, 2014

July 24, 2014

Posted by **Sam** on Saturday, August 16, 2008 at 3:59pm.

- Math 116 -
**Damon**, Sunday, August 17, 2008 at 9:31amx liters of .15 oj

then (10-x) of .05 oj

amount of oj in final = .15 x + .05(10-x)

= .09 *10 = .9

so

.15 x +.5 - .05x = .9

.1 x = .4

x = 4 liters of .15

then

6 liters of .05

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