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chem

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A solution is made by mixing 20.0 mL of toluene C6H5CH3d=0867gmL with 150.0 mL of benzene C6H6d=0874gmL. Assuming that the volumes add upon mixing, the molarity (M) and molality (m) of the toluene are

____M and

_____m.

  • chem - ,

    molarity=molestolulent/volume solution

    volume solution=.150+.020
    Moles toulene=20*.0867g/ml*molmass

    molarity=molestoluene/kg solvent

    kgsolvent=150*.0874 kg

    I am wondering what was the problem on this?

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