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December 20, 2014

December 20, 2014

Posted by **Michelle** on Wednesday, August 13, 2008 at 8:55am.

f(x) = 2+x x<(less than or equal to) -3

f(x) = x^2 x > -3 , x < 1

f(x) = 6 1 < (less than or equal to) x

I graphed it, but i don't know how to find the domain and range.

- Calculus -
**bobpursley**, Wednesday, August 13, 2008 at 9:01amThe domain is the allowed values of x (excluding the non allowed).

The range is the value of f(x), which you compute from x.

I will be happy to critique your thinking.

- Calculus -
**Michelle**, Wednesday, August 13, 2008 at 9:10amfor f(x) = 2+x : Domain: (negative infinity to -3]

Range: (-infinity to -1]

f(x) = x^2 : Domain: (-3,-1)

Range: (9,1)

f(x) = 6 : Domain: [-3,-1]

Range: [6]

i don't know how to put them all together though. is this right?

- Calculus -
**bobpursley**, Wednesday, August 13, 2008 at 9:28amon the second, the domain does not include -1 nor -3, you have to be careful on the non-included points. Same on the range, you can list it as 9-e,1+e where e is epsilion.

For an all together ,

domain: neginf to +inf

range: neginf to 9, excluding -1+e to 1 (check that).

There is an assortment of the ways you can describe this.

- Calculus -
**Brandon**, Wednesday, August 13, 2008 at 6:35pmThat assortment could include notations such as set builder and interval.

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