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March 25, 2017

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Factor completely:
x^10y^3 – 4x^9y^2 – 21x^8y

  • Algebra - ,

    we can immediately take out an x^8 and a y^1
    x^8 y ( x^2 y^2 - 4 x y - 21 )
    21 = 3 * 7
    3 - 7 = -4
    so try
    x^8 y ( x y - 7 ) ( x y + 3 )

  • Algebra - ,

    Thanks a lot, this really helps!

  • Algebra - ,

    Start by removing the common factor x^8 y.
    x^10y^3 – 4x^9y^2 – 21x^8y
    = x^8*y(x^2 y^2 -4 xy -21)
    The term in parentheses is a quadratic in the variable xy, and can be factored to

    (xy -7)(xy + 3).

    Now put it all together

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