we can immediately take out an x^8 and a y^1
x^8 y ( x^2 y^2 - 4 x y - 21 )
21 = 3 * 7
3 - 7 = -4
x^8 y ( x y - 7 ) ( x y + 3 )
Thanks a lot, this really helps!
Start by removing the common factor x^8 y.
x^10y^3 – 4x^9y^2 – 21x^8y
= x^8*y(x^2 y^2 -4 xy -21)
The term in parentheses is a quadratic in the variable xy, and can be factored to
(xy -7)(xy + 3).
Now put it all together
Answer this Question
Algebra - Ok I got two I need help with : 1. Factor Completely 7x^2 + 49x + 42 I...
algebra 1 - completely factor: 10y^2 -90
algebra - factor the following equation: 6x^2 - 21x - 9 i've tried to factor it ...
Math - Factor completely 3x^5-27x^4+21x^3
PreCal - Factor Completely: 10y^7 +26y^6 -12y^5
math - factor the polynomial completely... 3x-15+2xy-10y
algebra 2 - I am trying to factor the expression -8y^2+28y-60 but can't get an ...
Algebra 1 Answer Evaluation - Factor. 1. 30y^3 - 50y A: 10y(3y - 5y) 2. Factor ...
math - *simplify by combining like terms, if possible. then, remove the GCF and ...
algebra - x^2-21x-110 Factor