0.0100 Ba(OH)2 is dissolved in water to give 500.0 mL of solution

Question

0.0100 Ba(OH)2 is dissolved in water to give 500.0 mL of solution

calculate OH- concentration

would it be the molarity of Ba(OH)2 (0.0100 / 0.500) multiplied by two because there is twice as much OH??

Answer 1

Yes, you are correct. To calculate the OH- concentration in the solution, you need to consider the dissociation of Ba(OH)2. Ba(OH)2 dissociates into one Ba2+ ion and two OH- ions.

First, calculate the molarity of Ba(OH)2:

Molarity = moles of solute / volume of solution (in liters)

Molarity = 0.0100 moles / 0.500 L = 0.020 M

Since there are two OH- ions for each Ba(OH)2 molecule, the concentration of OH- ions will be twice the molarity of Ba(OH)2.

OH- concentration = 2 * (0.020 M) = 0.040 M

Therefore, the concentration of OH- ions in the solution is 0.040 M.

0.0100 Ba(OH)2 is dissolved in water to give 500.0 mL of solution

Yes.

Yes, you are correct. To calculate the OH- concentration in the solution, you need to consider the dissociation of Ba(OH)2. Ba(OH)2 dissociates into one Ba2+ ion and two OH- ions.