Calculate the solubility of Ag2CrO4 in grams/100mL of water?
(Ksp = 1.12x10^-12 )
I know how to calcuate the molar solubility, and I know how to convert it into grams/L...but I'm stuck on how to make it grams/100mL
Any Help would be awesome! =D thx!
convert the moles to grams, and then for volume, assume denstiy is the same as water (accurate for dilute solutions)
To calculate the solubility of Ag2CrO4 in grams/100mL of water, you can follow these steps:
1. Start with the Ksp expression for Ag2CrO4:
Ksp = [Ag+]^2 [CrO4^2-]
2. Since Ag2CrO4 dissociates into Ag+ and CrO4^2-, let's assume that x mol/L of Ag2CrO4 dissolves. This means the concentration of Ag+ and CrO4^2- ions will also be x mol/L.
3. Substitute the concentrations into the Ksp expression:
Ksp = (x)^2 (x) = x^3
4. Now, we can substitute the value of Ksp into the equation:
1.12x10^-12 = x^3
5. Solve for x by taking the cube root of both sides of the equation:
x = (1.12x10^-12)^(1/3)
≈ 5.33x10^-5 mol/L
6. Next, we can convert the molar solubility to grams/100mL using the following steps:
- Determine the molar mass of Ag2CrO4. The molar mass is:
(2 × atomic mass of Ag) + atomic mass of Cr + (4 × atomic mass of O)
= (2 × 107.87 g/mol) + 51.996 g/mol + (4 × 16.00 g/mol)
≈ 331.866 g/mol
- Calculate the solubility in grams/L by multiplying the molar solubility by the molar mass:
solubility = (5.33x10^-5 mol/L) × (331.866 g/mol)
≈ 0.0177 g/L
- Finally, convert the solubility to grams/100mL by dividing the solubility in grams/L by 10:
solubility = (0.0177 g/L) / 10
≈ 0.00177 g/100mL
Therefore, the solubility of Ag2CrO4 in grams/100mL of water is approximately 0.00177 g/100mL.
To calculate the solubility of Ag2CrO4 in grams/100mL of water, you can follow these steps:
Step 1: Find the molar solubility of Ag2CrO4.
The molar solubility (s) is the amount of a compound that dissolves in moles per liter (mol/L). In this case, you need to find the molar solubility based on the given Ksp value.
Step 2: Convert molar solubility to grams per liter (g/L).
To convert the molar solubility to grams per liter, you need to know the molar mass of Ag2CrO4. Add up the atomic masses of silver (Ag), chromium (Cr), and oxygen (O) to find the molar mass of Ag2CrO4. Then multiply the molar solubility (s) by the molar mass to get the solubility in grams per liter.
Step 3: Convert grams per liter (g/L) to grams/100mL.
To convert grams per liter to grams/100mL, you can use the following conversion factor: 1 liter = 1000 mL. Multiply the solubility in grams per liter by the conversion factor (1000 mL) to get the solubility in grams/100mL.
Therefore, the solubility of Ag2CrO4 in grams/100mL of water would be the result from step 3.